How do you simplify the expression #sin^2x/(1+cosx)#?

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15
Nov 27, 2016

Answer:

The answer is #=1-cosx#

Explanation:

We use

#sin^2x+cos^2x=1#

#sin^2x=1-cos^2x=(1+cosx)(1-cosx)#

Therefore,

#sin^2x/(1+cosx)=(cancel(1+cosx)(1-cosx))/cancel(1+cosx)#

#=1-cosx#

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