How do you simplify the expression #(sinthetacottheta)/costheta#?

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Answer 1 · 2016-09-12T15:20:06

#=1#

#(sinthetacottheta)/costheta#

#=sintheta/costhetatimescostheta/sintheta#

#=1#

Answer 2 · 2016-09-12T15:20:17

#1#.

The Exp. #=(sinthetacottheta)/costheta#

#={cancel(sintheta)(costheta/cancel(sintheta))}/costheta#

#=cancelcostheta/cancelcostheta#

#=1#.