How do you simplify the expression #(tantheta+cottheta)/csc^2theta#?

Question

3342 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-19T13:47:13

#tantheta#.

We will use the Trigo. Identity # : 1+cot^2x=csc^2x#

Now, the Exp. #=(tantheta+cottheta)/csc^2theta#

#=(1/cottheta +cottheta)/csc^2theta#

#=((1+cot^2theta)/cottheta)/csc^2theta#

#=(csc^2theta/cottheta)/csc^2theta#

#=1/cottheta#

#=tantheta#.