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How do you simplify the expression $tan θ cot θ - {cos}^{2} θ$ $tanthetacottheta-cos^2theta$ ?

1 Answer

Sep 3, 2016

${sin}^{2} θ$ $sin^2 theta$

Explanation:

Since $cot θ = \frac{1}{tan θ}$ $cot theta=1/tan theta$ , then

$tan θ cot θ = 1$ $tan theta cot theta=1$

so the given expression becomes:

$1 - {cos}^{2} θ$ $1-cos^2theta$

that is

${sin}^{2} θ$ $sin^2 theta$

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