How do you simplify the factorial expression ((n+2)!)/(n!)(n+2)!n!?

1 Answer
Feb 8, 2017

((n+2)!)/(n!) = (n+2)(n+1)(n+2)!n!=(n+2)(n+1)

Explanation:

Remember that:

n! =n(n-1)(n-2)...1

And so

(n+2)! =(n+2)(n+1)(n)(n-1) ... 1
\ \ \ \ \ \ \ \ \ \ \ \ \ \=(n+2)(n+1)n!

So we can write:

((n+2)!)/(n!) = ((n+2)(n+1)n!)/(n!)
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =(n+2)(n+1)