How do you simplify the factorial expression ((n+2)!)/(n!)(n+2)!n!?
1 Answer
Feb 8, 2017
((n+2)!)/(n!) = (n+2)(n+1)(n+2)!n!=(n+2)(n+1)
Explanation:
Remember that:
n! =n(n-1)(n-2)...1
And so
(n+2)! =(n+2)(n+1)(n)(n-1) ... 1
\ \ \ \ \ \ \ \ \ \ \ \ \ \=(n+2)(n+1)n!
So we can write:
((n+2)!)/(n!) = ((n+2)(n+1)n!)/(n!)
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =(n+2)(n+1)