# How do you simplify the radical expression (3-sqrt2)/(3 +sqrt2)?

$\frac{3 - \sqrt{2}}{3 + \sqrt{2}}$ becomes $\frac{\left(3 - \sqrt{2}\right) \left(3 - \sqrt{2}\right)}{\left(3 + \sqrt{2}\right) \left(3 - \sqrt{2}\right)}$
$\implies \frac{9 - 2 \left(3 \sqrt{2}\right) + 2}{9 - \left(2\right)}$
$\implies \frac{11 - 6 \sqrt{2}}{7}$