How do you simplify #((x-2)(2x+1))/((x^2-12)(x-2))#?

1 Answer

#((x-2)(2x+1))/((x^2-12)(x-2))=(2x+1)/(x^2-12)#

Explanation:

From the given expression, we can see a factor #(x-2)# both at the numerator and denominator

#((x-2)(2x+1))/((x^2-12)(x-2))=(cancel((x-2))(2x+1))/((x^2-12)cancel((x-2)))=(2x+1)/(x^2-12)#

God bless...I hope the explanation is useful.