How do you simplify (x^(2/3)*x^(4/6))^(-3)?

1. Simplify the fractions -> ${\left({x}^{\frac{2}{3}} \cdot {x}^{\frac{2}{3}}\right)}^{- 3}$
2. Multiplying with same bases, add exponents -> ${\left({x}^{\frac{4}{3}}\right)}^{- 3}$
3. Power to a power, multiply exponents -> ${x}^{- 4}$
Finally, ${x}^{- 4}$ = $\frac{1}{x} ^ 4$