How do you simplify #(x^2+4x-45)/(x^2+10x+9)# and find the restrictions on the variable?

1 Answer
Dec 3, 2017

#(x-5)/(x+1)# provided #x!=-9# and #x!=-1#

Explanation:

#(color(blue)(x^2+4x-45))/(color(red)(x^2+10x+9))#

#color(white)("XXX")=(color(blue)((x+9)(x-5)))/(color(red)((x+9)(x+1)))#

Provide #(x+9)!=0# (that is provided #x!=-9#)
[since division by zero is undefined]
we can divide the numerator and denominator by #(x+9)# to get:
#color(white)("XXX")=(color(blue)(x-5))/(color(red)(x+1))#

which is defined provided
#color(white)("XXX")x+1!=0# (or expressed differently, provided #x!=-1)#