How do you simplify #(x ^ { 2} - 6x - 2) / ( 10x - 30)#?

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Answer 1 · 2017-12-31T06:16:23

#(x-3)/10-11/(10(x-3)#

Use long division.

#(x^2-6x-2)/(10x-30)=x/10-(3x+2)/(10x-30)#

Then, divide #(3x+2)/(10x-30)#

#(3x+2)/(10x-30)=-3/10-11/(10x-30)#

Now, put that back into the original expression to get

#(x^2-6x-2)/(10x-30)=x/10-3/10-11/(10x-30)#

Simplify to get

#(x^2-6x-2)/(10x-30)=(x-3)/10-11/(10(x-3)#