How do you simplify $(x-2)(x+4)(x+6)$ ?

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Answer 1 · 2016-11-12T16:45:39

$x^3+8x^2+4x-48$

$[(x-2)(x+4)]$ $(x+6)$

$[x(x+4)-2(x+4)]$ $(x+6)$

$[x^2+4x-2x-8]$ $(x+6)$

$[x^2+2x-8]$ $(x+6)$

$x(x^2+2x-8)+6(x^2+2x-8)$

$x^3+2x^2-8x+6x^2+12x-48$

$x^3+8x^2+4x-48$

How do you simplify (x-2)(x+4)(x+6)(x-2)(x+4)(x+6)?