# How do you simplify (x^2-y^2)/(5x^3)*(y^2)/(15x^2y^5)?

May 7, 2018

$\frac{{x}^{2} - {y}^{2}}{75 {x}^{5} {y}^{3}}$

#### Explanation:

As per the question,

$\frac{{x}^{2} - {y}^{2}}{5 {x}^{3}} \cdot {y}^{2} / \left(15 {x}^{2} {y}^{5}\right)$

$\frac{{y}^{2} \left({x}^{2} - {y}^{2}\right)}{\left(5 {x}^{3}\right) \left(15 {x}^{2} {y}^{5}\right)}$

$\frac{{y}^{2} \left({x}^{2} - {y}^{2}\right)}{75 {x}^{5} {y}^{5}}$

$\frac{\left({x}^{2} - {y}^{2}\right)}{75 {x}^{5} {y}^{3}}$ ... [${y}^{2}$ gets cancelled by ${y}^{2}$ from ${y}^{5}$ so ${y}^{3}$ is remaining]