How do you simplify #(x^2-y^2)/x *( x^2+xy)/(x+y)#?
You factor the numerators of the two fractions and simplify like terms.
Your expression looks like this
You can factor the numerator of the first fraction by using the formula for the difference of two squares
In your case, you have
The numerator of the second fraction can be factored by using
Plug these into your original expression and simplify like terms present in the numerator and denominator
This will be equivalent to