How do you simplify #((x^2y^3)/(xy^3))^2#?

1 Answer
Oct 8, 2016

#x^2#

Explanation:

Take it one step at a time!

Dealing with what is inside the brackets first

Write as: #" "(x xx x xxy^3)/(x xxy^3)#

This is the same as:#" "x/x xx y^3/y^3xx x#

But #x/x = 1" and y^3/y^3=1# giving

#(1xx1xx x)^2 " " =" " x^2#