Question

How do you simplify `[(x^3-3x^2)/ (3x+6)] / [(x^3-8x^2+15x) / (6x^2-18x-60)`?

Answer 1

I found: `2x(x+2)/(x+3)`

Explanation:

I tried factorizing as much as possible to get (changing the division into a multiplication):

`=(x^2(x-3))/(3(x+3))xx(6x^2-18x-60)/(x(x^2-8x+15))=`

`=(x^2(x-3))/(3(x+3))xx(6(x+2)(x-5))/(x(x-3)(x-5))=`

`=(x^cancel(2)cancel((x-3)))/(cancel(3)(x+3))xx(cancel(6)^2(x+2)cancel((x-5)))/(cancel(x)cancel((x-3))cancel((x-5)))=`

`=2x(x+2)/(x+3)`