How do you simplify #x=lne^60#?

1 Answer
Feb 10, 2015

You can use the definition of logarithm and of Natural logarithm:
Natural logarithm is indicted by #ln# and has base #e#, so basically,
#log_e=ln#
also you can write:
#log_eb=lnb=x#
#-> e^x=b# (I)

In your case:
#ln(e^60)=x#
Using (I):
#e^60=e^x#
and #x=60#