How do you simplify #x\sqrt { 32y ^ { 5} } - y ^ { 2} \sqrt { 18y x ^ { 2} }#?

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Answer 1 · 2018-06-20T13:18:27

#xsqrt(32y^5)-y^2sqrt(18yx^2)#

#xsqrt(16xx2y^5)-y^2sqrt(9xx2yx^2)#

#4xsqrt(2y^5)-3y^2sqrt(2yx^2)#

#4xsqrt(2y^4xxy)-3y^2sqrt(2yx^2)#

#4xy^2sqrt(2y)-3xy^2sqrt(2y)#

#xy^2sqrt(2y)#

Answer 2 · 2018-06-20T13:19:55

#xy^2sqrt(2y)# for #x>=0# and #7xy^2sqrt(2y)# for #x<0#

Writing

#xsqrt(16y^4*2y)-y^2sqrt(9x^2*2y)#
and this is
#sqrt(2y)(4xy^2-3|x|y^2)#
and this is

#sqrt(2y)*xy^2# for #x>=0#
and

#7xy^2sqrt(2y)# for #x<0#