Question

How do you simplify `(x y ^ { 15} ) ^ { 0} 4x ^ { 2} x ^ { 3}`?

Answer 1

See a solution process below:

Explanation:

First, use this rule of exponents to simplify the term in parenthesis:

`a^color(red)(0) = 1`

`(xy^15)^color(red)(0)4x^2x^3 => 1 * 4x^2x^3 => 4x^2x^3`

Now, use this rule of exponents to complete the simplification:

`x^color(red)(a) xx x^color(blue)(b) = x^(color(red)(a) + color(blue)(b))`

`4x^color(red)(2)x^color(blue)(3) = 4x^(color(red)(2) + color(blue)(3)) => 4x^5`