# How do you simplify xsqrt(32x) + sqrt(128x)^3?

Apr 1, 2015

We allways try to take squares out of the root.

You may have noticed that $32 = 2 \cdot 16 = 2 \cdot {4}^{2}$
And that $128 = 2 \cdot 64 = 2 \cdot {8}^{2}$
And that ${x}^{3} = x \cdot {x}^{2}$

If we take these squares out, we get:

$x \sqrt{32 x} + \sqrt{128 {x}^{3}} =$

$4 x \sqrt{2 x} + 8 x \sqrt{2 x} =$

$12 \sqrt{2 x}$