How do you simplilfy #\frac{6x^{3}+34x^{2}-180x}{3x^{2}+18x-81}#?

1 Answer
Cem Sentin
Oct 16, 2017

#(6x^2-20x)/(3x-9)#

Explanation:

#(6x^3+34x^2-180x)/(3x^2+18x-81)#

=#2x(3x^2+17x-90)/[3(x^2+6x-27)]

=#(2x*(3x^2+27x-10x-90))/[3(x+9)(x-3)]#

=#(2x*(x+9)*(3x-10))/[3(x+9)(x-3)]#

=#(2x*(3x-10))/[3*(x-3)]#

=#(6x^2-20x)/(3x-9)#

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