How do you sketch #(x-2)^2+y^2=16#?

1 Answer
Nov 22, 2016

The basic equation to sketch a circle is:

#(x-a)^2 + (y-b)^2 = r^2#

Explanation:

Your value for #a# is clear: #a=2#
This is your #x#-coordinate.

Your value for #b# is hidden, but it's #0#.
This is your #y#-coordinate.

Now your radius is the square root of the right side of your function.

#sqrt(16) = 4 = r#

So, plug in your #x and y# coordinates; this is your center.

Then pick points #4# units around your center and sketch the rest of the circle.