How do you solve $0.5 (8 x - 4) = 10$ $0.5( 8x - 4) = 10$ ?

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How do you solve $0.5 (8 x - 4) = 10$ $0.5( 8x - 4) = 10$ ?

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Answer 1 · 2018-07-02T17:19:17

$x = 3$ $x = 3$

Explanation:

$0.5 (8 x - 4) = 10$ $0.5(8x - 4) = 10$
$0.5 \times 8 x - 0.5 \times 4) = 10$ $0.5 xx 8x - 0.5 xx 4) = 10$
$4 x - 2 = 10$ $4x - 2 = 10$
$x = 3$ $x = 3$

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How do you solve $0.5 (8 x - 4) = 10$ $0.5( 8x - 4) = 10$ ?

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How do you solve $0.5 (8 x - 4) = 10$ $0.5( 8x - 4) = 10$ ?