Question

How do you solve `0.73^x=0.25`?

Answer 1

`x = 4.405`

Explanation:

`0.25` is most certainly not one of the powers of `0.73`

The fact that the variable is in the index is an indication that you need to use logs.

`log0.73^x = log0.25" "larr` log both sides

`xlog0.73 = log0.25" "larr` power rule

`x = log0.25/log0.73" "larr` isolate `x`

`x = 4.405" "larr` use a calculator to get the value of `x`