# How do you solve #0x – 8y = -16# and #-8x + 2y = 36 #?

##### 2 Answers

#### Explanation:

We can use the elimination method to solve this system.

Equation 1:

Equation 2:

In the elimination method, we multiply each equation by a suitable number so that the two equations have a like term. For this problem, we will be focusing on

First, we will multiply *equation 1* by the coefficient of *equation 2*, and multiply *equation 2* by the coefficient of *equation 1*.

This means will will be multiplying equation 1 by

Equation 1:

Equation 2:

New Equation 1:

New Equation 2:

Now that both equations have a like term (

Now all we have to do is divide both sides by -64 to isolate and solve for

We can then substitute

Substitute

Add

Divide both sides by

**- - Alternate method: - -**

As you may have noticed, equation 1 has a term

We can then divide both sides by

Then substitute the value of

Subtract 4 from both sides of the equation:

Then divide both sides by -8 to solve for

The point

graph{(-8y+16)(2y-8x-36)=0 [-12.66, 12.65, -6.33, 6.33]}

So... in the first equation

Cancel out the minuses

Put this value in the second equation

Second equation

Put value

Multiply

Transfer the value 4

Transfer