How do you solve #-1/ 2( 10- 6v ) = 13( 9v + 3)#?

1 Answer
Gazza
Nov 2, 2017

#V=(-22)/57#

Explanation:

#(-1)/2(10 -6V)=13(9V+3)#
Let's start by using the distributive property.
#((-1)/2)(10) + ((-1)/2)(-6v)=(13)(9v)+(13)(3)#
#(-10)/2 + (6v)/2 = 117v +39#
#-5 + 3v = 117v + 39#
Subtract #color(red)(117v)# to both sides
#-5 + 3v - color(red)(117v) = cancel(117v) + 39 cancelcolor(red)(-117v)#
#-114v - 5 = 39#
The add #5# to both sides
#-114v cancel(-5) cancel(+5) = 39 + 5#
#-114v = 44#
Finally, divide both sides by #color(red)(-114)#
#(cancel(-114)v)/cancelcolor(red)(144) = 44/color(red)(114)#
# v = (-22)/57#

Related questions
Impact of this question
544 views around the world
You can reuse this answer
Creative Commons License