How do you solve 1/2abs(2x + 1 )> 2 ? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Ahmemaru ยท Stefan V. Mar 11, 2018 x > 3/2 or x < -5/2 in interval notation (-oo, -5/3) uu (3/2, oo) Explanation: 1/2|2x+1|>2 |2x+1|>4 2x+1>4 or 2x+1<-4 so -4>2x+1>4 -5>2x>3 -5/2>x>3/2 x > 3/2 or x < -5/2 (-oo, -5/3)uu(3/2, oo) Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 1778 views around the world You can reuse this answer Creative Commons License