Question

How do you solve `1/2x + 1/3y = 5 and 1/4x + y = 10` using substitution?

Answer 1

`x=4,y=9`

Explanation:

From the second equation we get
`y=10-1/4x`
plugging this in the first one
`1/2x+1/3(10-1/4x)=5`
`1/2x+10/3-1/12x=5`
Multplying by `12`
`6x+40-x=60`
`5x=20`
`x=4`
so
`y=9`