How do you solve #1- 3j = - 5#?

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Answer 1 · 2017-09-16T03:38:48

See a solution process below:

First, subtract #color(red)(1)# from each side of the equation to isolate the #j# term while keeping the equation balanced:

#-color(red)(1) + 1 - 3j = -color(red)(1) - 5#

#0 - 3j = -6#

#-3j = -6#

Now, divide each side of the equation by #color(red)(-3)# to solve for #j# while keeping the equation balanced:

#(-3j)/color(red)(-3) = (-6)/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))j)/cancel(color(red)(-3)) = 2#

#j = 2#