How do you solve 1/(3m)+(6m-9)/(3m)=(3m-3)/(4m)?

1 Answer
Nov 27, 2016

m=0 " "Or" "m=23/15

Explanation:

1/(3m)+(6m-9)/(3m) = (3m-3)/(4m)
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rArr(1+6m-9)/(3m)=(3m-3)/(4m)
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rArr(-8+6m)/(3m)=(3m-3)/(4m)
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rArrcolor(blue)((-8+6m)xx4m = (3m-3)xx3m)
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rArr-32m + 24m^2 = 9m^2-9m
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rArr-32m + 24m^2 - 9m^2+9m=0
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rArr15m^2-23m=0
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rArrm(15m-23)=0
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m=0
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Or
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15m - 23 =0rArr15m = 23rArrm=23/15