Question

How do you solve `1- 3x \leq - 14+ 2x`?

Answer 1

`x >= 3`

Explanation:

First do the necessary mathematics to isolate the `x` terms on one side of the inequality and the constants on the other side of the inequality while keeping the inequality balanced:

`1 - 3x + 3x + 14 <= -14 + 2x + 3x + 14`

`1 - 0 + 14 <= 0 + 2x + 3x`

`15 <= 5x`

Now divide each side of the inequality by `5` to solve for `x` while keeping the equation balanced:

`15/5 <= (5x)/5`

`15/5 <= (cancel(5)x)/cancel(5)`

`3 <= x`

To get the solution in terms of `x` we need to reverse or "flip" the inequality:

`x >= 3`