How do you solve #1 / 5x + 1/3y = - 1 / 15# and #1 / 5x + 2y = 8 / 5# using substitution?
We can solve each equation for
We can now solve for
And now we can substitute back into one of the original equations to solve for
Which gives us the point
I would usually simplify the equations to get rid of the fractions first, but in this case we have identical terms in each equation, so I will solve for those first.
We can substitute the other sides of each equation for