How do you solve #1/ 6( 12z - 18) = 2z - 3#?

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Answer 1 · 2016-11-16T14:23:50

#0 = 0# Therefore the solution for this problem is all numbers. Any number you substitute for #z# will solve this problem.

Step 1) Expand the terms in parenthesis:

#(12z)/6 - 18/6 = 2z - 3#

#2z - 3 = 2z - 3#

Step 2) Solve for #z#

#2z - 3 - 2z + 3 = 2z - 3 - 2z + 3#

#0 = 0#

The solution for this problem is all numbers. Any number you substitute for #z# will solve this problem.