# How do you solve #1/(6b^2)+1/(6b)=1/(b^2# and check for extraneous solutions?

##### 1 Answer

Nov 27, 2016

Extraneous solution is

#### Explanation:

Write as:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~

We are 'not allowed' to have 0 as a denominator. The proper name for this is that the expression is 'undefined'

So the extraneous solution is

For