How do you solve #1- 6r = 13- 2r#?

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Answer 1 · 2016-11-19T02:25:06

#r = -3#

Step 1) Add #6r# to each side of the equation to begin isolating and solving for #r# and ensuring the equation stays balanced:

#1 - 6r + 6r = 13 - 2r + 6r#

#1 - 0 = 13 + 4r#

#1 = 13 + 4r#

Step 2) Subtract 13 from each side of the equation to further isolate #r# and to continue to keep the equation balanced:

#1 - 13 = 13 - 13 + 4r#

#-12 = 0 + 4r#

#-12 = 4r#

Step 3) Divide each side by #4# to finally solve for #r# while keeping the equation balanced;

#(-12)/4 = (4r)/4#

#-3 = 1r#

#r = -3#