Question

How do you solve `1/(6x^2)=1/(2x)+7/(6x^2)` and check for extraneous solutions?

Answer 1

x = -2

Explanation:

`1/(6*x^2) - 7/(6*x^2) = 1/(2*x)`

`-6/(6*x^2) = 1/(2*x)`

`-x^2 = 2*x`

`x=-2`