How do you solve #1/(r-2)+1/(r^2-7r+10)=6/(r-2)# and check for extraneous solutions?
1 Answer
Oct 29, 2016
Explanation:
Note that
So the given equation can be written:
#1/(r-2)+1/((r-2)(r-5)) = 6/(r-2)#
Multiply through by
#1+1/(r-5)=6#
(noting that
Subtract
#1/(r-5) = 5#
Take the reciprocal of both sides to get:
#r-5 = 1/5#
Add
#r = 26/5#
Since