Question

How do you solve `1/x=6/(5x)+1` and check for extraneous solutions?

Answer 1

I found: `x=-1/5`

Explanation:

We can use `5x` as common denominator and rearrange as:
`5/cancel(5x)=(6+5x)/cancel(5x)`
`5x=5-6`
`5x=-1`
`x=-1/5`
which is an acceptable solution