Question

How do you solve `(1 - y)/(1 + y) = 2/3`?

Answer 1

`y=1/5`

Explanation:

When we have 2 fractions equal to each other then the way to eliminate the fractions is to `color(blue)"cross-multiply"`

`rArra/b=c/drArr ad=bc`

here we obtain

2(1 + y) = 3(1 - y)

multiply out brackets.

hence : 2 + 2y = 3 - 3y

now collect like terms , y to the left and numbers on right. Remember to change the sign of a term when it is moved from one side to the other.

thus : 2y + 3y = 3 - 2 → 5y = 1

divide both sides by 5

`rArr(cancel(5)^1 y)/cancel(5)^1=1/5rArry=1/5`