How do you solve #-10+1/3y>2/3#?

1 Answer
Jim G.
Oct 20, 2016

#y>32#

Explanation:

The first step here is to multiply all terms by 3 to eliminate the fractions.

#(3xx-10)+cancel(3)xxy/cancel(3)> cancel(3)xx2/cancel(3)#

#rArr-30+y>2#

add 30 to both sides of the inequation.

#cancel(-30)cancel(+30)+y>2+30#

#rArry>32" is the solution"#

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