How do you solve #-10+1/3y>2/3#?
1 Answer
Oct 20, 2016
Explanation:
The first step here is to multiply all terms by 3 to eliminate the fractions.
#(3xx-10)+cancel(3)xxy/cancel(3)> cancel(3)xx2/cancel(3)#
#rArr-30+y>2# add 30 to both sides of the inequation.
#cancel(-30)cancel(+30)+y>2+30#
#rArry>32" is the solution"#
