How do you solve #10+ 15z = 5( 3z + 2)#?

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Answer 1 · 2017-04-17T18:24:31

See the entire solution process below:

First, expand the terms in parenthesis on the right side of the equation by multiplying each term in parenthesis by the term outside the parenthesis:

#10 + 15z = color(red)(5)(3z + 2)#

#10 + 15z = (color(red)(5) xx 3z) + (color(red)(5) xx 2)#

#10 + 15z = 15z + 10#

Next, subtract #color(red)(10)# from each side of the equation:

#-color(red)(10) + 10 + 15z = 15z + 10 - color(red)(10)#

#0 + 15z = 15z + 0#

#15z = 15z#

Now, divide each side of the equation by #color(red)(15)#:

#(15z)/color(red)(15) = (15z)/color(red)(15)#

#(color(red)(cancel(color(black)(15)))z)/cancel(color(red)(15)) = (color(red)(cancel(color(black)(15)))z)/cancel(color(red)(15))#

#z = z#

The solution is therefore the set of all numbers. Any number you select will be equal to itself.