How do you solve $10 = 3 (r + 1) + 1$ $10= 3( r + 1) + 1$ ?

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Answer 1 · 2018-01-16T16:25:27

$r = 2$ $r = 2$

$10 = 3 (r + 1) + 1$ $10 = 3(r+1) + 1$

$10 - 1 = 3 (r + 1)$ $10 - 1 = 3(r+1)$

$9 = 3 (r + 1)$ $9 = 3(r+1)$

Divide $3$ $3$ both sides giving:
$3 = r + 1$ $3 = r+1$

$3 - 1 = r$ $3-1 = r$

$2 = r$ $2 = r$

How do you solve 10= 3( r + 1) + 110=3(r+1)+110= 3( r + 1) + 1?