How do you solve #-10| - 6n + 2| = - 80#?

1 Answer
Jun 24, 2017

Use the definition of the absolute value function:

#|A| = {(A;A>=0),(-A; A < 0):}" [1]"#

Explanation:

Given: #-10| - 6n + 2| = - 80#

Divide both sides by -10:

#| - 6n + 2| = 8#

Using the form of equation [1]:

#8= {(-6n+2;-6n+2>=0),(6n-2;-6n+2<0):}#

Simplify the restrictions:

#8= {(-6n+2;1/3>=n),(6n-2;1/3 < n):}#

Write this as two equations:

#-6n+2 = 8; 1/3 >=n# and #6n-2=8;1/3 < n#

#n = -1; 1/3 >=n# and #n=5/3;1/3 < n#

Because the restrictions are not violated, therefore, we can drop them:

#n = -1# and #n=5/3 larr# answers

Check:

#-10| - 6(-1) + 2| = - 80# and #-10| - 6(5/3) + 2| = - 80#

#-10|8| = - 80# and #-10|-8| = - 80#

Both result in #-80 =-80# so the answers check.