How do you solve $10 (b - 5) \geq - 40$ $10( b - 5) \geq - 40$ ?

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Answer 1 · 2017-09-19T02:26:09

See a solution process below:

First, divide each side of the inequality by $10$ $color(red)(10)$ eliminate the need for parenthesis while keeping the inequality balanced:

$\frac{10 (b - 5)}{10} \geq - \frac{40}{10}$ $(10(b - 5))/color(red)(10) >= -40/color(red)(10)$

$(color(red)(cancel(color(black)(10)))(b - 5))/cancel(color(red)(10)) >= -4$

$b - 5 >= -4$

Now, add $color(red)(5)$ to each side of the inequality to solve for $b$ while keeping the inequality balanced:

$b - 5 + color(red)(5) >= -4 + color(red)(5)$

$b - 0 >= 1$

$b >= 1$

How do you solve 10( b - 5) \geq - 4010(b−5)≥−4010( b - 5) \geq - 40?