# How do you solve #−10 + log_ 3 (n + 3) = −10#?

##### 1 Answer

Jan 25, 2016

#### Answer:

#### Explanation:

#-10 + log_3(n+3) = -10#

First of all, add

#<=> color(white)(xx) log_3(n+3) = 0#

To "get rid" of the

#<=> color(white)(xx) 3^(log_3(n+3)) = 3^0#

... don't forget that for any number

#<=> color(white)(xxxxx) n + 3 = 1#

... subtract

#<=> color(white)(xxxxxx) n = -2#