How do you solve $10^(x+2) - 12 = 22$ and find any extraneous solutions?

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Answer 1 · 2016-07-22T10:18:07

The Soln. is $x=-0.4685$

$10^(x+2)-12=22 rArr 10^(x+2)=12+22=34$

$rArrlog_(10)10^(x+2)=log_(10)34$

$rArr (x+2)log_(10)10=1.5315$ ..................[Using LogTable]

$rArr (x+2)*1=1.5315$

$rArr x+2=1.5315$

$rArr x=1.5315-2$

$rArr x=-0.4685$ is the Soln.

How do you solve 10^(x+2) - 12 = 22 10^(x+2) - 12 = 22 and find any extraneous solutions?