How do you solve #10f - 2= 78 #?

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Answer 1 · 2018-04-08T20:40:47

#f = 8#

Here's how I did it:

First, we add #2# to both sides of the equation:
#10f - 2 quadcolor(red)(+quad2) = 78 quadcolor(red)(+quad2)#

#10f = 80#

Now we divide both sides by #10#:
#(10f)/color(red)10 = 80/color(red)10#

#f = 8#

Hope this helps!

Answer 2 · 2018-04-08T20:41:14

#f=8#

Our first step would be to add #2# to both sides. Remember, we want to isolate #f#. Doing this, we get:

#10f=80#

Our last step would be to divide both sides by #10# to isolate #f#. We arrive at

#f=8#

Hope this helps!