How do you solve #10x^211x6=0#?
2 Answers
There are two solutions:
Explanation:
Since this question is given in standard form, meaning that it follows the form:
I think it's worthwhile to mention that
Now, we just plug our values into the equation like this:
For these type of problems, you will obtain two solutions because of the
Now, we subtract 19 from 11 and divide by 20:
Next, plug each value of x into the equation separately to see if your values give you 0. This will let you know if you performed the calculations correctly or not
Let's try the first value of
BOOM, this value of x is correct since we got 0!
Now, let's see if the second value of
That value of x is correct as well!
Thus, the two possible solutions are:
If (5x + 2) = 0 , then
If (2x  3) = 0, then
Explanation:
Factor the equation by pieces ( Easier than the quadratic if it works)
10 can be factored into 5 x 2 or 10 x 1
6 can be factored into 3 x 2 or 6 x 1
The sum of the factors after being multiplied must add to 11
The bigger factor combination must be negative so 5 x 3 = 15
The smaller factor combination must be positive so 2 x + 2 = +4

15 + ( + 2) = 11

2 x (3) = 6
Now that we have the factors we can solve the equation by making each factor equal to 0.