How do you solve #10x - 6x - 4- 1= 7- 12+ 2x + 2x#?

1 Answer
smendyka
Oct 31, 2017

See a solution process below:

Explanation:

First, combine like terms on each side of the equation:

#(10 - 6)x + (-4 - 1) = (7 - 12) + (2 + 2)x#

#4x + (-5) = -5 + 4x#

#4x - 5 = -5 + 4x#

#-5 + 4x = -5 + 4x#

Because both sides of the equation are true this equation is true for any value of #x#. Therefore the solution set to this problem is the set of all Real Numbers: #{RR}#

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