How do you solve #-11=-10+\frac{k}{4}#?

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Answer 1 · 2017-11-13T14:05:42

See a solution process below:

First, add #color(red)(10)# to each side of the equation to isolate the #k# term while keeping the equation balanced:

#color(red)(10) - 11 = color(red)(10) - 10 + k/4#

#-1 = 0 + k/4#

#-1 = k/4#

Now, multiply each side of the equation by #color(red)(4)# to solve for #k# while keeping the equation balanced:

#color(red)(4) xx -1 = color(red)(4) xx k/4#

#-4 = cancel(color(red)(4)) xx k/color(red)(cancel(color(black)(4)))#

#-4 = k#

#k = -4#