How do you solve #11h - ( 2h - 1) = 118#?

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Answer 1 · 2017-04-03T12:22:42

See the solution process below

First, remove the individual terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#11h - 2h + 1 = 118#

Next, combine like terms on the left side of the equation:

#(11 - 2)h + 1 = 118#

#9h + 1 = 118#

Then, subtract #color(red)(1)# from each side of the equation to isolate the #h# term while keeping the equation balanced:

#9h + 1 - color(red)(1) = 118 - color(red)(1)#

#9h + 0 = 117#

#9h = 117#

Now, divide each side of the equation by #color(red)(9)# to solve for #h# while keeping the equation balanced:

#(9h)/color(red)(9) = 117/color(red)(9)#

#(color(red)(cancel(color(black)(9)))h)/cancel(color(red)(9)) = 13#

#h = 13#